Question

Q. If alpha and Beta are the zeroes the quadratic polynomial x2 - 7x + 12 , then 1/alpha + 1/beta is...
(a) 7/12
(b) -7/12
(c) 12
(d) 7​

Answer 1

Answer:

the correct wnswer is (a) 7/12

Answer 2

Answer:

Option a

Step-by-step explanation:

Given :-

α and β are the zeroes of x^2-7x+12

To find :-

Find the value of (1/α)+(1/β) ?

Solution:-

Given quardratic polynomial = x^2-7x+12

On Comparing this with the standard quadratic Polynomial ax^2+bx+c

a = 1

b = -7

c=12

We know that

Sum of the zeroes = -b/a

= α+ β

= -(-7)/1

=> 7

and

Product of the zeroes = c/a

αβ = 12/1

= 12

we have

α+ β = 7 and αβ = 12

Now the value of (1/α)+(1/β)

=> (α+ β )/αβ

=> 7/12

(1/α)+(1/β) = 7/12

Answer:-

The value of (1/α)+(1/β) for the given problem is 7/12

Used formulae:-

• The standard form of quadratic Polynomial is ax^2+bx+c

• Sum of the zeroes = -b/a

• Product of the zeroes = c/a