Question

Q. If angle A = 90°, AC= 9cm and angle Q=90°,PR= 9cm, PQ=5cm, then by which congruence criterion ∆BAC=∆RQP​

Answer 1

Answer:

sorry yaar I don't explain your question

Answer 2

Answer:

for find a side AB let AB be x

cos 90° = H\B

0 = x\9

9× 0 = x

0. = x

. . AB = 0

given:

Triangle first

angle A = 90°

AC = 9cm

AB = 0

Triangle secound

angle Q = 90°

PR = 9cm

PQ = 5cm

angle A = angle Q (each angle is 90°)

AC = PR (both sides are equal)

∆ BAC = ∆RQP

( by SAS property)