Q.
If cosA= x/y , then find the value of TanA.【+_+】
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Hi ,
Cos A = x/y -----( 1 )
SinA = √ 1 - cos² A
= √ 1 - ( x/y )²
= y / √( y² - x² ) ----( 2 )
TanA = sinA / cosA
= [ y/ √ ( y² - x² ) ]/ ( x/ y )
= y² / [ x ( √y² - x² ) ]
I hope this helps you .
: )
Cos A = x/y -----( 1 )
SinA = √ 1 - cos² A
= √ 1 - ( x/y )²
= y / √( y² - x² ) ----( 2 )
TanA = sinA / cosA
= [ y/ √ ( y² - x² ) ]/ ( x/ y )
= y² / [ x ( √y² - x² ) ]
I hope this helps you .
: )
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