Question

Q. If cotØ=7/8
then find the value of cot^2 Ø​

Answer 1

If cot theta=7/8 evaluate (1+sin theta)(1 - sin theta)/ (1+cot theta)(1-cos theta) Get the answers you need, now! ... 7 and 8 i.e sqrt7^2+8^2=√113 so now sinθ=8/√113 and cosθ=7/√113 ... on solving we get 49/(√113-7)√113.

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Answer 2

$: \implies \cot \theta = \dfrac{7}{8}$

$: \implies { \cot}^{2} \theta = \bigg( \dfrac{7}{8} \bigg) ^{2} = \boxed{\bf\red{ \dfrac{49}{64} }} \bigstar$