Question

Q: If diameter of conductor is made four time of its original value then find the ratio between old resistance and new resistance ?

Solve it Please !
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Answer 1

Answer:

If you stretch the wire it's resistivity will not change (all because it depends upon nature of wire and temperature only) but also it's volume remains constant so cross section area also changes. As the volume remains constant natural cross section area × natural length = new cross section area × 4× natural length( as the wire is stretched four times) . So new cross section area = natural cross section area / 4

Now assuming that you are aware with the formula for calculating the resistance if length resistivity and cross section area us given which is R = π L/A where π is resistivity , l is length and A is cross section area . Let the natural resistance be R. So

R = πL/A (EQUATION 1)

R (New resistance) = π4L /(A÷4)

= 16πL/A (EQUATION 2)

Divide both the equations and you get will get new resistance equal to 16 times the given resistance

Explanation:

hope it helps you

have a great day

Answer 2

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If diameter of conductor is made four time of its original value then find the ratio between old resistance and new resistance ?