Q. If one side of a square is increased by 2 metres and the other side is decreased by 2 metres, a rectangles of perimeter 48 m is formed. Find the side of the square.
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SOLUTION
Given,
One side of a square= (x+2)
other side = (x-2)
Perimeter= 48
A/q
=) Perimeter of rectangle= 2(l+b)
=) 2(x+2+x-2)=48
=) 2(2x)=48
=) 4x= 48
=) x= 48/4
=) x= 12m
hope it helps ☺️
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