Q.)If P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD, then:
a. ar(APB) > ar(BQC)
b. ar(APB) < ar(BQC)
c. ar(APB) = ar(BQC)
d. None of the above. (I need an explanation too thanks :))
Answers
Answered by
1
Answer:
C) area of (APB) = area of (BQC).
Step-by-step explanation:
If ABCD is parallelogram such that P and Q are any two points lying on the sides DC and AD respectively, then we have proved that area of (APB) = area of (BQC).
Answered by
1
Answer:
b. ar(APB) < ar(BQC)
Step-by-step explanation:
It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same set of parallel lines AD and BC.
Area (ΔBQC) = 1/2 Area (ABCD)(1)
Similarly, ΔAPB and parallelogram ABCD lie on the same base AB and between the same set of parallel lines AB and DC.
Area (ΔAPB) = 1/2 Area (ABCD)(2)
Area (ΔBQC) = Area (ΔAPB)
=ar(APB) < ar(BQC)
Similar questions