Question

Q. If radius of earth is R, find the altitude at which value of 'g'
will be half of that at the surface of earth.
pls dont give irrevelant ans
pls help its urgent
class 9 physics
pls give complete steps​

Answer 1

Explanation:

We know, g/g' = r2/R 2 , where g is gravitational force on earth, g' is gravitational force at a height.

Given g' = g/2

g = r 2gR

2 = 2⇒r 2=2R 2

⇒r=R 2=R+h⇒h=R(2−1)

=R(1.414−1)

=0.414R

Answer 2

Explanation:

We know, g/g' = r^2 /R^2

where g is gravitational force on earth,

g' is gravitational force at a height.

Given g' = g/2

g ′ = g R^2 / r^2

= g/2

⇒ r^2 = 2R^2

⇒ r = R√2

= R+h

⇒ h = R(√2 −1)

=R (1.414−1)

= 0.414R