Question

Q)If sin^2(theta+alpha)=a, cos^2(theta+beta)=b, then sin(alpha-beta)=?​

Answer 1

Answer:

hello

Step-by-step explanation:

We have sin(θ + α) = a - (i)

sin(θ + β) = b - (ii)  

Ultimately we need to eliminate A from    sin(A+x)=a and sin(A+y)=b

cos(x-y)=cos{(A+x)-(A+y)}=cos(A+x)cos(A+y)+sin(A+x)sin(A+y)

{cos(x-y)-ab}^2=cos(A+x)^2cos^2(A+y)=(1-a^2)(1-b^2)

Simplify and rearrange