Question

Q.If the car starts from rest and moves with an acceleration of 5m/s^2 in 30 sec calculate the final velocity of the car .

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Answer 1

$\frak{\huge{AnswEr :}}$

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Given Parameters :

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Initial velocity of the car is 0 m/s.

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Acceleration of the car is 5 m/s².

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Time taken by the car is 30 sec.

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Neet to calculate: The final velocity of the car.

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Given that the car starts from rest and moves with an acceleration of 5m/s² in 30 sec.

We have to calculate the final velocity of the car. It can be calculated by using the equation of motion.

You can easily derive the equations of motion by algebraic, calculus & by graphic method.

By using the first equation of motion :

$\bf{\dag} \boxed{\bf{v = u + at}}$

Where,

v = Final velocity.

u = Initial velocity.

a = Acceleration.

t = Time taken.

Substituting all the given values :

$\sf{:\implies v = 0 + 5 \times 30} \\ \\ \\ \sf{:\implies v = 0 + 150} \\ \\ \\ \sf{:\implies \boxed{ \frak{ \pink{v = 150}}}}$

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$\therefore\textsf{\underline{The final velocity of the car is \textbf{150}\textbf{m/s}}} ^{{\textsf{\textbf{2}}}}$

Answer 2

Answer:

$0 + \frac{1}{2} \times 5 \times {8}^{2}$

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

${s}^{2}$

=40×4=160 m.

So, the total distance traveled by the car is

$160 + 160 = 320$