Q. If the point A(0,2) is equidistant from the points B(3,p) and C(p,5) find p. Also find the lenght of AB
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Answer:
p=1
Step-by-step explanation:
AB^2=AC^2. (given)
by distance formula,
= [√(3-0)^2+(p-2)^2]^2 =[√(p-0)^2+(5-2)]^2
= (3)^2 + (p-2)^2 = (p)^2 + (3)^2
=
=
equating the equation,we get
p=1
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