Question

Q. If the sum of square of the zeros of the polynomials 6x^2+x+k is 25/36 then find the value of K ?

Answer 1

SOLUTION;___✍️

We know that in ax^2+bx+c,

sum of zeroes is -b/a

product of zeroes= c/a

so, in this polynomial,

sum of zeroes= -1/6

product of zeroes= p/6

by using (a+b)^2= a^2+b^2+2ab

(-1/6)^2= 25/36+2p/6 {if a & b are zeros}

1/36= 25/36+ 12p/36

=1= 25+12p

=12p= 1-25

=p= -24/12

therefore= -2 Ans.

_________&_______

MARK BRAINLIEST✓✓✓

Answer 2

Answer:

Step-by-step explanation: