Q. if x=2sin^2Ѳ, y=2cos^2Ѳ+1 then find value of x+y.
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Answer:
x=2sin^2 theta
y= 2cos^2 theta +1
so x+y=2sin^2 theta +2cos^2 theta +1
x+y = 2(sin^2theta +cos^2 theta) +1
x+y= 2(1)+1
x+y=2+1
x+y = 3
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