Question

Q. In a Davis steering mechanism the distance between pivot of front axle 2 points
(b) 120cm, and the length of wheel base is (1) 260cm. When the vehicle
moving straight path the angle of (a) inclination of track arm to the
verticalls
degree
21.99
12.99
19.33
32.81​

Answer 1

Answer:

21.99

i hope you help is mu luck

Answer 2

The angle of inclination of the track arm  to the vertical degree is 12.99

Step by Step Explanation:

Given: Distance between pivot of front axle of David steering is 120 cm

The length of wheel base is 260cm

To find: Inclination of track arm to the vertical degree

Formula used: tanα= 2b/c

As per the given data,

Distance between the axle (c) = 120 cm = 1.2 m

Wheel base (b) = 260 cm = 2.6 m

Let,

α = Inclination of the tract arm to the longitudinal axis

we know that,

$tan \alpha = \frac{c}{2b}$

⇒ $\frac{1.2}{(2)(2.6)}$

⇒ $\frac{1.2}{5.2}$

⇒$0.230$

$tan \alpha = 0.230$

$\alpha = 12.99$

Final answer:

The angle of inclination of the track arm to the vertical degree is 12.99

#SPJ2

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