Question

Q: In a departmental store customer may choose any combination of Butter, Eggs and Bread. The Probability that a customer chooses Bread is 0.55, Eggs and Butter 0.25, Bread and Eggs 0.15, Bread and Butter 0.30, Bread or Eggs 0.78, Brad or Butter 0.85 and all the three 0.12. Find the probability that a customer chooses either Bread or Butter or Eggs.​

Answer 1

Answer:

0.95

Step-by-step explanation:

Let probability of bread be P(B), probability of eggs be P(E)

probability of butter be P(T)

Given P(B)=0.55

P(EnT)=0.25

P(BnE)=0.15

P(BnT)=0.30

P(BuE)=0.78

P(BuT)=0.85

P(BnEnT)=0.12

P(BuT)=P(B)+P(T)-P(BnT)

0.85=0.55+P(T)-0.30

P(T)=0.85-0.55+0.30=0.6

P(BuE)=P(B)+P(E)-P(BnE)

0.78=0.55+P(E)-0.15

P(E)=0.78-0.55+0.15=0.38

To find, P(BuEuT)

P(BuEuT)= P(B)+P(E)+P(T)-P(BnE)-P(EnT)-P(BnT)+P(BnEnT)

=0.55+0.38+0.6-0.15-0.25-0.30+0.12

=0.95