Question

Q. In a triangle ABC , AB perpendicular BC, FG perpendicular BC and DE perpendicular AC. Prove that triangle ADE similar to triangle GCF.

please anyone solve it........

Answer 1

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Answer 2

Answer:

In the given figure we have to prove Δ ADE and Δ FGC are similar.

Now from Δ ADE and Δ GFC we have,

∠AED=∠GFC [right-angles],

∠DAE=∠FGC [ AD∥GF andAC intersector, similar angles].

Then ∠ADE=∠GCF [Remaining angles].

∴ΔADE is similar to ΔGFC.[By AA test] [henceproved]

Step-by-step explanation:

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