Question

Q.: In the following figure. If PQ II ST,
LPQR = 105°, ZRST = 125º. Find ZQRS
S
1959
P
105
R​

Answer 1

Answer:

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Answer 2

Let us draw a line RN

RN || ST

RS is transversal

therefore <SRN + <RST = 180° ( Interior angle of same side of a transversal is supplementary)

<RST = 125°

<SRN+125°=180°

<SRN=180°-125°

<SRN=55°

PQ||ST ( given)

ST||RN( by construction)

Therefore PQ ||RN

<PQR =<QRN ( Alternate angles are equal)

<PQR=105°

<QRN= <QRS + <SRN

<SRN =55°

55°+<QRS =105°

<QRS=105°-55°

<QRS = 50°

I HOPE IT'S HELPFUL