Question

Q: In the given circuit ,the potential difference between point A and B is 18V and charge on 2uF capacitor is 24uC . The energy stored in capacitor C is?​

Answer 1

Answer:

1 μF

Explanation:

Voltage across 2μFcapacitor is 2 /24=12V

So, voltage across 6μF capacitor is 18−12=6V

Hence, charge on 6μF capacitor 6×6=36μC

So, charge on C capacitor =36−24=12μC

The value of C is

C=  12/ 12   =1μF

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