Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF ∠ADC= 25°, THEN THE MEASURE OF ∠AEB IS
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In the given figure join AC and BD then ∠CAD=∠CBD=90
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∵ Angle is formed by diameter.
Also AB∣∣CD
∴∠BAD=∠ADC=25
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∠BAC=∠BAD+∠CAD=25+90=115
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∴ ∠ADB=180
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−25−∠BAC=40
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Also, ∠AEB=∠ADB=40
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Angle subtended by same chord on the circle are equal.
Step-by-step explanation:
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