Question

Q. IN THE GIVEN FIGURE. AB II CD AND 0 IS THE CENTER OF THE CIRCLE. IF ∠ADC= 25°, THEN THE MEASURE OF ∠AEB IS

Answer 1

Answer:

first of all, Where is E ?

Answer 2

Answer:

40°

Step-by-step explanation:

In the given figure join AC and BD then ∠CAD=∠CBD=90o

∵  Angle is formed by diameter.

Also AB∣∣CD

∴∠BAD=∠ADC=25o

∠BAC=∠BAD+∠CAD=25+90=115o

∴ ∠ADB=180o−25−∠BAC=40o

Also, ∠AEB=∠ADB=40o

Angle subtended by same chord on the circle are equal.

please mark it as brianlist ans

HOPE IT WILL HELP YOU PLESE MARK IT AS BRIANLIST ANS AND FOLLOW ME....