Question

Q: in triangle ABC and DEF, AB = 3.8cm, BC = 6cm . AC = 3√2. where as in triangle DEF, DE = 7.6cm , EF = 12cm then the value of DF is??

Answer 1

Answer:

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>Maths

>Triangles

>Pythagoras Theorem and its Converse

>In ABC, AB = 6√(3) cm, AC ...

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In △ABC,AB=63cm,AC=12cm and BC=6cm. The ∠B is :

A

120o

B

60o

Your Answer

C

90o

Correct Answer

D

45o

Medium

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Correct option is

C

90o

Given:

In △ABC

AB=63cm

AC=12cm

BC=6cm

Solution:

AC2=144

AB2=108

BC2=36

Since,

AC2=AB2+BC2

∴ By Converse of Pythagoras Theorem,

△ABC is an Right Angle Triangle at B.

∴∠B=90o

like this

Answer 2

∆ABC~∆DEF [AA Rule]

By corresponding side of similar triangle,

AB/DE=BC/EF=AC/DF

6/12=AC/DF

1/2=3√2/DF

DF=2(3√2)

DF=6√2

DF is 6√2cm