Question

Q: integrate (x^3-5x^2-8x+10)/√8 dx?
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Answer 1

3

x

2

+

d

d

x

[

−

5

x

2

]

+

d

d

x

[

−

8

x

]

+

d

d

x

[

5

]

3x2+ddx[-5x2]+ddx[-8x]+ddx[5]

Evaluate

d

d

x

[

−

5

x

2

]

ddx[-5x2].

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3

x

2

−

10

x

+

d

d

x

[

−

8

x

]

+

d

d

x

[

5

]

3x2-10x+ddx[-8x]+ddx[5]

Evaluate

d

d

x

[

−

8

x

]

ddx[-8x].

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3

x

2

−

10

x

−

8

+

d

d

x

[

5

]

3x2-10x-8+ddx[5]

Differentiate using the Constant Rule.

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3

x

2

−

10

x

−

8

3x2-10x-8

y

=

x

3

−

5

x

2

−

8

x

+

5

y=x3-5x2-8x+5