Q is a point on the side CB of a right angled triangle ABC, right angled at C, where CQ = 2/3 BC. Prove that 9 AQ2 = 9 AC2 + 4 BC2
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To prove : (1) 9AQ2 = 9AC2 + 4BC2 (2) 9BP2 = 9BC2 + 4AC2 (3) 9(AQ2 + BP2) = ... 9(AQ 2 + BP 2 ) = 13(AC 2 + BC 2 ) = 13AB 2 (∆ABC is right angle C then AC 2 + BC ...
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