Question

Q is a point on the side SR of a triangle PSR such that pq = pr .prove that ps pq

Answer 1

given : PSR is a triangle.and PQ  = PR
TPT : PS > PW

proof : 

in Δ PQR, PQ = PR 

therefore
∠PQR = ∠PRQ

now ∠prq >∠psq 
∠PRQ> PSQ or ∠PRS > PSR
now in the triangle PSR : ∠PRS> ∠PSR

therefore  PS >PR  
thus PS > PQ

HENCE ITS PROVED

Answer 2

Answer:

Step-by-step explanation:

In Triangle PRQ

PR=PQ, Therefore it is an Isosceles triangle

LPRQ = LPQR(Isosceles triangle theorom)

In Triangle PQS

LPQS = LPSQ

(ext. L is greater than the angle opposite to it )

PS>PQ (side opposite to the greater angle is bigger)

HENCE PROVED