Q is the mid-point of the side
OR of parallelogram ROSE. A line through R is
drawn parallel to QS meets ES at T and OS produced at P. Prove that RP = 2RT.
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Answer:
ABCD is a parallelogram
SL=LR (L is mid-point)
LQ∥SN
In △SRN, L is mid-point of SR and LQ parallel to SN
∴RQ=QN (by mid-point theorem)
SRRL=SNLQ
2RLRL=SNLQ
∴SN=2LQ
∵RQ=QN
RQ=21RN
similarly SP=21RN
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