Question

Q is the point on the side SR of a triangle PSR such that PQ is equal to PR.Prove that PS is greater than PQ.

Answer 1

Answer:

given: PSR is a triangle. and PQ = PR

TPT: PS > PQ

proof:

in ΔPQR, PQ = PR

therefore

PQR=PRQ

..........(1) [angles opposite to equal sides are equal]

now ∠PQR > ∠PSQ [since exterior angle of a triangle is always greater than each of its interior angles]

therefore ∠PRQ > PSQ or ∠PRS > PSR

now in the triangle PSR : ∠ PRS > ∠PSR

therefore PS>PR [sides opposite to greater angles are greater]

thus PS > PQ

which is the required result.

hope this helps you.

cheers!!

Answer 2

Answer:

Step-by-step explanation:

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