Question

Q It is possible to find the sides ofright-angled triangle, with lengths which are whole numbers, by substituting different values of x into the expression(a) 2xsqr +2x+1 (b) 2xsqr+2x (c) 2x+1 (a) represents the hypotenuse(b) and (c) represents other 2 sides.1) find the sides of triangleswhen x=1, 2, 3, 4 and 5 .​

Answer 1

Answer:

Step-by-step explanation:

a=2x^2 +2x+1 [hypotenuse]

b=2x^2+2x

c= 2x+1

sides of triangle when x=1

a=2+2+1

=5

b=2+2

=4

c=2+1

=3

sides of triangle when x=2

a = (2 x 4)+(2 x 2)+1

=8+4+1

=13

b = (2 x 4) + (2 x 2)

=8+4

=12

c=(2x2)+1

=5

sides of triangle when x=3

a= (2 x 9)+(2 x 3)+1

=18+6+1

=25

b= (2 x 9)+(2 x 3)

=18+6

=24

c=(2 x 3)+1

=6+1

=7

sides of triangle when x=4

a= (2 x 16)+(2 x 4)+1

=32+8+1

=41

b=(2 x 16)+(2 x 4)

= 32+8

=40

c=(2 x 4)+1

=8+1

=9

sides of triangle when x=5

a= (2 x 25)+(2 x 5)+1

= 50 + 10 +1

=61

b=(2 x 25)+(2 x 5)

= 50 + 10

=60

c=(2 x 5)+1

=10+1

=11

HOPE IT HELPS YOU