Q. it is possible to have a polyhedron with :
1. 6 faces, 8 vertices, 11 edges
2. 4 faces, 3 vertices, 5 edged
3. 5 faces, 6 vertices, 9 edges
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Step-by-step explanation: BY EULER'S FORMULA
=> F + V = E +2
1. 6 + 8 = 11 +2
= 14 ≠ 13
∴ IT IS NOT POSSIBLE TO HAVE A POLYHEDRON
2. 4 + 3 = 5 +2
=> 7 = 7
∴ IT IS POSSIBLE TO HAVE A POLYHEDRON
3. 5+ 6 = 9+2
=> 11 = 11
∴ IT IS POSSIBLE TO HAVE A POLYHEDRON
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