Math, asked by happinessz, 1 year ago

Q.Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was?

Plzzz help me this question

Answers

Answered by Swayze
7
Hy..
Friend..

I solved your queation...
Its really good question..

Follow me step by step

1st step is

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
=======================
You know speed formula..
=======================
Speed = Distance/Time.
Or Time = Distance/Speed.

times taken to covered
a distance of 50 miles on his first trip = 50/x hr. Okey
Then......
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

THANKYOU

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Answered by adityasaran
1
Let the speed in the first trip be x km/hr
Distance covered = 50 miles
= 50* 1.6
= 80 km
Time taken = 50/x hr

In the later trip,
Distance covered = 300 miles
= 300*1.6
= 480 km
Speed = 3x km/hr
Time taken = 480/3x. hr
= 160/x hr


New time compared to old time = (160/x)/ (50/x) = 160/50
= 16 : 5

happinessz: Bro your ans was wrong
happinessz: Ans correct is 100/ x hr. Is a new time compared with the old time.
happinessz: But its okeyy thankyou you help me...
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