Q.Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was?
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Answers
Answered by
7
Hy..
Friend..
I solved your queation...
Its really good question..
Follow me step by step
1st step is
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
=======================
You know speed formula..
=======================
Speed = Distance/Time.
Or Time = Distance/Speed.
times taken to covered
a distance of 50 miles on his first trip = 50/x hr. Okey
Then......
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
THANKYOU
Friend..
I solved your queation...
Its really good question..
Follow me step by step
1st step is
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
=======================
You know speed formula..
=======================
Speed = Distance/Time.
Or Time = Distance/Speed.
times taken to covered
a distance of 50 miles on his first trip = 50/x hr. Okey
Then......
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
THANKYOU
happinessz:
Thankyou bro you again helping me... I follow you bro...
Answered by
1
Let the speed in the first trip be x km/hr
Distance covered = 50 miles
= 50* 1.6
= 80 km
Time taken = 50/x hr
In the later trip,
Distance covered = 300 miles
= 300*1.6
= 480 km
Speed = 3x km/hr
Time taken = 480/3x. hr
= 160/x hr
New time compared to old time = (160/x)/ (50/x) = 160/50
= 16 : 5
Distance covered = 50 miles
= 50* 1.6
= 80 km
Time taken = 50/x hr
In the later trip,
Distance covered = 300 miles
= 300*1.6
= 480 km
Speed = 3x km/hr
Time taken = 480/3x. hr
= 160/x hr
New time compared to old time = (160/x)/ (50/x) = 160/50
= 16 : 5
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