Question

Q - length of a rope is 200/1 m. Two pieces of lengths 161/5 m and 381/4 m are cut down from it. Find the length of remaining rope.

(Solve step by step method⬆⬆)

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Answer 1

Answer:

Step-by-step explanation:

Lengths of pieces are 161/5 and 381/4

Let remaining length=X

Therefore,

200=(161/5)+(381/4)+X

200=(644+1905+20x)/20

4000=2549+20x

4000-2549=20x

1451=20x

X=1451/20

X=72.55 m

Remaining length of rope=72.55