Q. Let P be the set of all no. obtained by multiplying 5 distinct integers b/w 1 and 100. What is the largest integer n such that 2^n divides atleast one element of P?
(A) 8 (B) 20 (C) 24 (D) 25
Answers
Answered by
3
Some Powers of 2 and their multiples are
8, 16, 24, 32, 48, 64, 80, 96
96 * 80 * 64 * 48 * 32
= 2^5 * 3 * 2^4 * 5 * 2^6 * 2^4 * 3 * 2^5
= 45 * 2^24
Maximum n = 24
8, 16, 24, 32, 48, 64, 80, 96
96 * 80 * 64 * 48 * 32
= 2^5 * 3 * 2^4 * 5 * 2^6 * 2^4 * 3 * 2^5
= 45 * 2^24
Maximum n = 24
Similar questions