Question

Q. Lis parallel to m, intersected bya transversal, if
the measure of two corresponding angles are (7x-20)
degrees and (3x+20 ) degrees , the value of x =
degrees​

Answer 1

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✤ Required Answer:

✒ GiveN:

• line l is parallel to line m
• They are intersected by a transversal.
• Corresponding angles are (7x - 20)° and (3x + 20)°

✒ To FinD:

• Value of x in degrees?

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✤ How to solve?

For solving this question, we have to know a concept:

• When two parallel lines are intersected by a transversal, the corresponding angles are equal to each other.
• Similarly, alternate angles on either side are equal to each other.
• Angles on the same side of transversal whether externally or internally, they add upto 180° i.e. they are supplementary to each other.
• Vertically opposite angles are equal.

⚡ So, let's solve this question...

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✤ Solution:

We know that,

• Corresponding angles are equal here,

Reason:

• Line l and line m are parallel
• They are intersected by a transversal.

So, we can write it as,

➝ 3x + 20 = 7x - 20

➝ 3x - 7x = -20 - 20

➝ -4x = -40

➝ x = 10°

☃️ Value of x in degrees = 10°

☀️ Hence, solved !$!$

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Answer 2

◘ Given ◘

$\bigstar$ l is parallel to m, intersected by a transversal.

$\bigstar$ The measure of two corresponding angles are (7x - 20)° and (3x + 20)°.

◘ To Find ◘

The value of x in degrees.

◘ Solution ◘

We know, the corresponding angles are equal when the 2 lines are parallel and are intersected by a transversal.

$\bullet\ \sf{\underline{\underline{REFER\ TO\ THE\ ATTACHMENT}}}$

We get →

∠ABC = ∠BDE

Solving further :-

⇒ (7x - 20)

° = (3x + 20)°

⇒ 7x - 3x = 20 + 20

⇒ 4x = 40

⇒ x = 40/4

⇒ x = 10°

Therefore, the value of x is 10 degrees.