Question

Q.log (2x - 3) + log 3 = log (2x + 7)
solve for x !​

Answer 1

Answer:

Given, log(2x + 3) (6x2 + 23x + 21) = 4 - log(3x + 7) (4x2 + 12x + 9) Read more on Sarthaks.com - https://www.sarthaks.com/261867/solve-for-x-the-following-equation-log-2x-3-6x-2-23x-21-4-log-3x-7-4x-2-12x-9og (2x + 3) (6x2 + 23x + 21)

= 4 - log 3x + 7 ( 4x2 + 12x + 9)

⇒ log (2x + 3) (6x2 + 23x 21)

+ log (3x + 7) (4x2 + 12x + 9) = 4

⇒ log (2x + 3) (2x + 3) (3x + 7) + log (3x + 7) (2x + 3)2 x = 4

⇒ 1 + log (2x + 3) (3x + 7) + 2 log (3x + 7) (2x + 3) = 4

[ Using log ab = a + log b and log an = n log a]

NOTE THIS STEP

⇒ log (2x + 3) (3x + 7) + 2/ log (2x + 3) (3x + 7) = 3 [ Using logab