Question

Q

Maximum Mark. 4.00 Negative Mark.
25 g of a solute of molar mass 250 g/mol is dissolved in 100 mL of water to obtain a solution whose density is 1.25 g/ml. The molarity and molality of
solution are respectively,
0.75 and 1​

Answer 1

Answer:

0.1125/1000=0.8m.

Explanation:

No. of moles of solute =25250=0.1 moles

Molarity =No. of moles of soluteVolume of solvent in litre=0.11001000=1M

Molality =no. of moles of solutemass of solvent in kg

Mass =d×V

=1.25×100=125g

Molality =0.1125/1000=0.8m.