Q. Meera has a piece of canvas whose area is 551 m². She uses it to have a conical tent made, with a base radius of 7 m. Assuming that all the stitching margins and the wastage incurred while cutting, amounts to approximately 1 m² find the volume of the tent that can be made with it.
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Step-by-step explanation:
Let Tent have Radius = r = 7m
Let slant height = l m
let height = h m
Area of canvas = area available for making tent + wastage 551 m² = area available for maing tent + 1 m² area available for making tent = 551 m² - 1 m² = 550 m²
Area available for making tent = Curved surface area of conical tent 550 = πrl
550 = 22 × 1 × l
22 × 1 × l = 550
l = 550/22 m
l = 25 m
we know that
l² = h²+ r²
25² = h² + 7²
25² - 7² = h²
h² = 25² - 7²
h² = (25 - 7) (25 + 7)
h² = (18) (32)
h =√18(32)
h = √(9 × 2) × (32)
h =√(9) × (64)
h = √(3²) × (8²)
h = 3 × 8
h = 24 m
volume of tent = 1/3πr²h
= 1/3 × 22/7 × 7 × 7 × 24 m³
= 22 × 1 × 7 × 8 m³
= 1232 m³
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