Question

Q.N.3-On dividing x3+3x2+3x+1by x=0 then we get remainder
(а) -9
(b) 1 (с)-3
(d) 0​

Answer 1

Question:-

On dividing x3+3x2+3x+1by x=0 then we get remainder

(а) -9

(b) 1 (с)-3

(d) 0

Required Answer:-

Remainder = 1

Solution:-

Apply remainder theorem, we get

=> x = 0

Replacing x by 0 we get,

=> x^3 + 3x^2 + 3x + 1

=> (0)^3 + 3(0)^2 + 3(0) + 1

=> 0 + 0 + 0 + 1

=> 1

Hence,

Remainder = 1

Answer 2

$\huge\sf\red{Question:-}$

On dividing x3+3x2+3x+1by x=0 then we get remainder = ?

$\huge\mathbf\pink{Answer}$

Applying remainder theorem

$\red\longrightarrow$ x = 0

Now, replacing x by 0 we get,

$\red\dashrightarrow$ $x^3$ + $3x^2$ + 3x + 1

$\red\dashrightarrow$ $(0)^3 + 3(0)^2 + 3(0) + 1$

$\large\pink\longrightarrow$ 0 + 0 + 0 + 1

$\huge\pink\longrightarrow$ 1

Hence,

Remainder = 1

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