Math, asked by vijaygavendra, 1 month ago

Q. N. 5 Find a quadratic polynomial each with the numbers-5 and 6 as the sum and product of its zeroes respectively also find the zeros of the polynomials.​

Answers

Answered by sanjuyadav00
0

mark m

Step-by-step explanation:

༒☬ᶜᴿᴬᶻᵞkíllє®™r☬༒मोहबत को जो निभाते हैं उनको मेरा सलाम है, और जो बीच रास्ते में छोड़ जाते हैं उनको, हुमारा ये पेघाम हैं, “वादा-ए-वफ़ा करो तो फिर खुद को फ़ना करो, वरना खुदा के लिए किसी की ज़िंदगी ना तबाह करो”

Answered by mamtachauhan507
0

Answer:

mark as brainlist

Step-by-step explanation:

(i)

4

1

, -1

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

4

1

x−1=0

4x

2

−x−4=0

(ii)

2

,

3

1

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

2

x+

3

1

=0

Multiply by 3 to remove denominator,

3x

2

−3

2

x+1=0

(iii) 0,

5

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

−0x+

5

=0

x

2

+

5

=0

(iv) 1, 1

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

−1x+1=0

x

2

−x+1=0

(v)

4

−1

,

4

1

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

4

−1

x+

4

1

=0

Multiply by 4

4x

2

+x+1=0

(vi) 4, 1

Using the quadratic equation formula,

x

2

−(Sum of root)x+(Product of root)=0

Substitute the value in the formula, we get

x

2

−4x+1=0

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