Math, asked by student8961, 4 days ago

Q) Nita has deposited Rs.25,000 in a deposit scheme which gives 8% p.a.(per annum) compounded half-yearly.How much amount will she get back at the end of 1 year 6 months to the nearest rupee? (with step-by-step explanation)​

Answers

Answered by mathdude500
29

\large\underline{\sf{Solution-}}

Given that,

Nita has deposited Rs.25,000 in a deposit scheme which gives 8% per annum compounded half-yearly.

So, we have

Principal, P = Rs 25000

Rate of interest, r = 8 % per annum compounded half yearly.

Time, n = 1 year 6 months = 3/2 years

We know,

Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded half yearly for n years is given by

\boxed{\sf{  \:\rm \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{200} \bigg]}^{2n}  \:  \: }} \\

So, on substituting the values, we get

  \:\rm \: Amount \:  =  \: 25000 {\bigg[1 + \dfrac{8}{200} \bigg]}^{3}  \:  \:  \\

\rm \: \:  =  \: 25000 {\bigg[1 + \dfrac{1}{25} \bigg]}^{3}  \:  \:  \\

\rm \: \:  =  \: 25000 {\bigg[\dfrac{25 + 1}{25} \bigg]}^{3}  \:  \:  \\

\rm \: \:  =  \: 25000 {\bigg[\dfrac{26}{25} \bigg]}^{3}  \:  \:  \\

\rm \: =  \: 28121.60 \\

\rm \: =  \: 28122 \:   \:  \:  \:  \:  \: \{to \: nearest \: rupee \} \\

Hence,

Amount received after one year and six months = Rs 28122.

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Additional Information :-

1. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by

\boxed{\sf{  \:\rm \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{100} \bigg]}^{n} \:  \: }}

2. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by

\boxed{\sf{  \:\rm \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n} \:  \: }}

3. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by

\boxed{\sf{  \:\rm \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{1200} \bigg]}^{12n} \:  \: }}

Answered by talpadadilip417
25

Step-by-step explanation:

Here, the conversion period is \dfrac{1}{2} year.

Thus, in 1 year 6 months, there will be 3 conversion periods. Original principal =₹ 25,000

Interest for the first half-year

 \red{ \tt=₹ \dfrac{25000 \times \cancel 8^{ {}^{ {}^{4} } }  \times \dfrac{1} {\cancel{2}}}{100}  =₹250 \times 4=₹ 1,000 }

∴ Amount at the end of first half-year,

i.e., the principal for the second-year

=₹ 25,000+₹ 1,000=₹ 26,000

Interest for the second half-year

 \pink{ \tt=₹  \:  \: \dfrac{26000 \times \cancel 8 ^{ {}^{ {}^{4} } }  \times \dfrac{1} {\cancel{2}}}{100} = ₹ \: 260 \times 4=₹  \:  \: 1,040 .}

∴ Amount at the end of second half-year, i.e., The principal for the third half-year

=₹ 26,000+₹ 1,040=₹ 27,040

Interest for the third half-year

 \color{maroon} \tt=₹  \:  \:  \: \dfrac{27040 \times \cancel 8  {}^{ {}^{ {}^ {\cancel{4}} } } \times \dfrac{1} {\cancel{2}}} {\cancel{100_{_{_{25}}}}}   = ₹ \:  \:  \dfrac{27040}{25} =₹  \:  \: 1,081.60

∴ Amount at the end of third half-year =₹

 \color{darkcyan} \begin{array}{l} \tt 27,040+  ₹1,081.60  \\ \tt =₹  \:  \: 28,121.60  \\   \tt=₹ \:  \:  28,122  \:  \:  \:  \:  \:  \:  \: \text{(to the nearest rupee)}  \end{array}

Thus, Nita will get back ₹28,122 at the end of 1 year 6 months.

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