Question

Q.No.06 For an isolated
1 point
systemAU = 0; what will be AS
if spontaneous work is done?
>0
<O

O=0
None of above​

Answer 1

Answer:

For an isolated system, ∆U = 0 and for a spontaneous process, total entropy change must be positive.

For example, consider the diffusion of two gases A and B into each other in a closed container which is isolated from the surroundings.

The two gases A and B are separated by a movable partition. When partition is removed, the gases begin to diffuse into each other and the system becomes more disordered. It shows that ∆S > 0 and ∆U = 0 for this process.

Morever, ∆S=q

rev

/T = ∆H / T

= ∆U + p∆V /T = p∆V /T

i.e. T ∆S or ∆S > 0

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