Q.No.06 For an isolated
1 point
systemAU = 0; what will be AS
if spontaneous work is done?
>0
<O
O=0
None of above
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Answer:
For an isolated system, ∆U = 0 and for a spontaneous process, total entropy change must be positive.
For example, consider the diffusion of two gases A and B into each other in a closed container which is isolated from the surroundings.
The two gases A and B are separated by a movable partition. When partition is removed, the gases begin to diffuse into each other and the system becomes more disordered. It shows that ∆S > 0 and ∆U = 0 for this process.
Morever, ∆S=q
rev
/T = ∆H / T
= ∆U + p∆V /T = p∆V /T
i.e. T ∆S or ∆S > 0
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