Question

Q NO 10 please answer my question

Answer 1

we know it is a rectangle
here given,
length=150m
breadth=50m
length of wire required=
for this we find the perimeter of rectangle
perimeter of rectangle is
$2(l + b)$
then perimeter is=
$2(150 + 50) \\ 2(200) \\ 400 \\ then \: perimeter = 400m \\ the \: cost \: of \: fencing = 25 \\ then \: the \: cost \: = 400 \times 25 = 10000 \: answer$