Q NO. 10 please no funny answers
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Let the numerator be 'x'
Case 1 ----
Denominator is 1 less than 3 times of numerator = x/(3x-1)
Case 2-----
If 13 is added to numerator and 8 is added to the denominator then fraction becomes equal to 1.
(x+13) / (3x-1+8) = 1
(x+13) / (3x+7) = 1
(x+13) = (3x+7)
-2x = -6
x = 3
put this x value to x/(3x-1)
3/[3(3) - 1]
= 3/8 is your original fraction
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