Question

q.no 11,12,13.........

Answer 1

HELLO!!

ANSWERS:

11) Angle 1 = 60°
Angle 2 = 44°
Angle 3 = 76°

Angle 3 = 180° - 136° [Angles on a straight line=180°]

Angle 3 = 44°

Angle 2 = 180° - 104° [Angles on a straight line=180°]

Angle 2 = 76°

Let angle 1 be x.

76° + 44° + x = 180° [Angle sum property of triangle]

120° + x = 180°

x = 180° - 120°

x = 60°

Angle 1 = 60°
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12)Angle CAB = 45°
Angle ABC = 60°
Angle ACB = 75°

Angle CAB = 45° [Vertically opposite angles are equal]

Angle ACB = 180° - 105° [Angles on a straight line=180°]

Angle ACB = 75°

Let Angle ABC be x.

45° + 75° + x = 180° [Angle sum property of triangle]

120° + x = 180°

x = 180° - 120°

x = 60°

Angle ABC = 60°
_________________________

13)x = 60°
y = 90°

Let Angle ACB be p.

30° + 30° + p = 180° [Angle sum property of triangle]

60° + p = 180°

p = 180° - 60°

p = 120°

Angle ACB = 120°

x = 180° - 120° [Angles on a straight line=180°]

x = 60°

Let Angle DEC be q.

30° + 60° + q = 180° [Angle sum property of triangle]

90° + q = 180°

q = 180° - 90°

q = 90°

y = 180° - 90° [Angles on a straight line=180°]

y = 90°
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HOPE IT HELPS YOU!!