Question

Q.No.11. Calculate the amount when P= 1000, R = 10% per annum (compounded annually) Time
2 years​

Answer 1

Step-by-step explanation:

Here, Principal P = Rs. 1000

R =10% per annum and n=2 years

∴ Amount after 2 years =

$p(1 + \frac{r}{200} ) ^{2n}$

$= 1000 \times (1 + \frac{10}{200} ) {}^{2 \times 2}$

$= 1000 \times (1 + \frac{1}{20} ) {}^{4}$

$= 1000 \times ( \frac{21}{20}) {}^{4}$

$= 1000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20}$

$= 1215.50$

Hence, compound interest = Amount - Principal

$= 1215.50 - 1000$

$= 215.50$

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Answer 2

Answer:

is the right answer mark as brainlist