Question

Q.No : 11. The cost of two tables and three chairs is $705. If the table costs $40 more than the chair, find the cost of the table and the chair.

Answer 1

$<b>Heya mate. (^_-). Solution below.$
====================================

• Let the cost of 1 table be 'x'.

• And, cost of 1 chair be 'y'.



• Then, according to the question, cost of table is $ 40 more than the chair.

=> x = y + 40... [equation i]



• Again, according to the question, cost of two tables and three chairs is $ 705.

=> 2 (x) + 3 (y) = 705

or, 2(y + 40) + 3(y) = 705....[from equation i]

=> 2y + 80 + 3y = 705

=> 2y + 3y = 705 - 80

=> 5y = 625

=> y = 625/5

=> y = 125


• Therefore, cost of one chair = y = $ 125.



• Now, substituting the value of y in equation i.

x = y + 40

= 125 + 40

= 165.


• Therefore, cost of one table = x = 165


$<marquee>Hence, cost of one table is 165 dollars and cost of one chair is 125 dollars.</marquee>$
====================================

Thank you.. ;-)