Question

Q.No : 12
Equivalent Weight of KMnO4v in Basic
medium
OA) 31.5
OB) 158
C) 53
OD) 52.66​

Answer 1

Answer:

52.66 is the equivalent weight of KMnO4v

Answer 2

Answer:

In acidic medium: MnO

4

−

+8H

+

+5e

−

→Mn

+2

+4H

2

O

In basic medium: MnO

4

−

+e

−

→MnO

4

2−

In neutral medium: MnO

4

−

+4H

+

+3e

−

→MnO

2

+2H

2

O

Equivalent mass is molecular mass divided by number of electrons gained.

In acidic medium, equivalent weight =

5

Molecularweight

In basic medium, equivalent weight =

1

Molecularweight

In neutal medium, equivalent weight =

3

Molecularweight

Ration of equivalent mass =

5

Molecularweight

:

1

Molecularweight

:

3

Molecularweight

Ratio of equivalent mass =3:15:5

PLEASE MARK ME AS BRAINLIST