Question

Q.No: 13. Marks : 2
If A and B are two events such that P(A) = 1/3, P(B) = 3/4 and P(AUB) = 11/12 then find P(A/B)​

Answer 1

Answer ⤵️

P(A)= 1/3

P(B)= 1/4

Now, P(AUB) = 11/12

=> P(A)+ P(B) - P(A∩B) = 11/12

=> P(A∩B) = ( 1/3 + 3/4 ) - 11/12 = 2/12 = 1/6

Therefore,

P(B/A)= P(A∩B) / P(A)

= (1/6) / (1/3)

= 1/2

Answer 2

Step-by-step explanation:

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