Question

Q.No.2(A): Answer the following.
1. Write electronic configuration of Fe, Ne, Go, Ga
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Answer 1

Explanation:

In order to write the Iron electron configuration we first need to know the number of electrons for the Fe atom (there are 26 electrons). Once we have the configuration for Fe, the ions are simple. When we write the configuration we'll put all 26 electrons

In writing the electron configuration for Iron the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Iron go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the next six electrons. We now shift to the 4s orbital where we place the remaining two electrons. After the 4s is full we put the remaining six electrons in the 3d orbital and end with 3d6.

Therefore the Iron electron configuration will be 1s22s22p63s23p64s23d6.

Answer 2

Explanation:

1. Fe, 2,8,8,8
2. Ne,2,8
3. Ge,2,8,8,8,6
4. GA, 2,8,8,8,5

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