Question

Q no 2:
Joan sits on a see saw at 2m from pivot and his weight is 300N. On the
other hand side, Tom sits at the distance of 1m from pivot. What is the
Weight of the Tom?

Answer 1

Given - Weight of Joan - 300 N.

Distance of Joan from pivot - 2 metre

Distance of Tom from pivot - 1 metre

Find - Weight of Tom.

Solution - To create equilibrium on the see saw the torque has to be balanced. The formula to calculate the torque is - F * d, where f stands for force and d represents distance.

Thus, representing in mathematical expression -

Force 1 * D1 = Force2 * D2.

Left hand side represents Joan and right hand side represents Tom.

Keeping the values in equation-

300*2 = Force2*1

Force2 = 600 N.

Hence, weight of Tom is 600 N.