Q no 22 in the picture
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➡️Consider the side of square = x
▶️since the diameter of circle is 10 cm
O is the centre of circle so
▶️OC = OD = OA = 10/2 = 5 cm
Now
✅OB = x-5 ..( see diagram clearly )
✍️AB=x/2
How AB is x/2
In ∆ABO & ∆ CBO
✍️angle ABO = angle CBO..(90°)
✍️BO = BO ..common
✍️AO = OC ...( radius of circle )
▶️both are congruent by RHS Congruency Rule
✅means AB = BC by C.p.c.t
✅AB² + OB² = AO²
✍️(x/2)²+(x-5)² =5²
✍️x²/4+(x²+25-10x) = 25
✍️x²+4(x²+25-10x) = 25×4
✍️x²+4x²+25×4-40x=25×4
✍️5x²-40x=0
✍️5x(x-8)=0
✍️x=0 or x-8=0 and it's
✍️x=8
➡️x = sides = 8 cm
➡️area of square = 8² = 64 cm² or unit²
your solution...
▶️since the diameter of circle is 10 cm
O is the centre of circle so
▶️OC = OD = OA = 10/2 = 5 cm
Now
✅OB = x-5 ..( see diagram clearly )
✍️AB=x/2
How AB is x/2
In ∆ABO & ∆ CBO
✍️angle ABO = angle CBO..(90°)
✍️BO = BO ..common
✍️AO = OC ...( radius of circle )
▶️both are congruent by RHS Congruency Rule
✅means AB = BC by C.p.c.t
✅AB² + OB² = AO²
✍️(x/2)²+(x-5)² =5²
✍️x²/4+(x²+25-10x) = 25
✍️x²+4(x²+25-10x) = 25×4
✍️x²+4x²+25×4-40x=25×4
✍️5x²-40x=0
✍️5x(x-8)=0
✍️x=0 or x-8=0 and it's
✍️x=8
➡️x = sides = 8 cm
➡️area of square = 8² = 64 cm² or unit²
your solution...
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saurabhsavarn:
please answer my other questions too
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64 cm² is answer dear friend
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