Question

q.no 4 ,5,6 and 8 please urgent

Answer 1

Hi there! Good question!

Q4.⇒Supplementary angles are the angles that are equal to 180°.
i)Names of the supplementary angles:-
∠1 and ∠4, ∠1 and ∠2, ∠2 and ∠3, ∠3 and ∠4, ∠5 and ∠6, ∠6 and ∠7, ∠7 and ∠8, ∠8 and ∠5, ∠9 and ∠10, ∠10 and ∠11, ∠11 and ∠12, ∠12 and ∠9.

⇒Angles forming X and are vertically opposite are called vertically opposite angles,
ii)Names of the vertically opposite angles:-
∠1=∠3, ∠2=∠4, ∠5=∠7, ∠6=∠8, ∠9=∠11, ∠10=∠12Hi there! Good question!

⇒Supplementary angles are the angles that are equal to 180°.
i)Names of the supplementary angles:-
∠1 and ∠4, ∠1 and ∠2, ∠2 and ∠3, ∠3 and ∠4, ∠5 and ∠6, ∠6 and ∠7, ∠7 and ∠8, ∠8 and ∠5, ∠9 and ∠10, ∠10 and ∠11, ∠11 and ∠12, ∠12 and ∠9.

⇒Angles forming X and are vertically opposite are called vertically opposite angles,
ii)Names of the vertically opposite angles:-
∠1=∠3, ∠2=∠4, ∠5=∠7, ∠6=∠8, ∠9=∠11, ∠10=∠12.
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Q5.Given= ∠1= 145°
∠3= ∠1 = 145° (Vertically Opposite ∠S)

∠1 + ∠2 = 180° (Linear Pair)
145° + ∠2 =180°
∠2= 180°-145°= 35°

∠4=∠2 (Vertically Opposite ∠S)
∠4= 35°
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Q6.i) 90°+4x°+1°+53°= 180°
144°+4x°= 180°
4x°= 180°-144° = 36°
x°= 36°÷ 4 = 9°
∴x°= 9°

ii) 3x°-2°= 94 (Vertically Opposite)
3x°= 94°+ 2°= 96°
x°= 96°÷ 3 = 32°
∴x°= 32°

iii) x°+ 57°= 180°
x°= 180°-57°= 123°
∴x°= 123°

iv) 3x+2x+x= 180° (Supplementary Angles)
6x= 180°
x= 180°÷ 6 = 30°
∴x°= 30°
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Q8.i) x= 55° (Vertically opposite)
y+55°= 180° (Linear pair)
y=180°-55°= 125°
z= 125° (Vertically opposite)

ii) 13°- x= 17°-x (Vertically Opposite)
-x+x= 17°-13°
x= 4°
y+4°= 180° (Linear Pair)
y=180°-4°= 176°
z=176° (Vertically Opposite)

iii) z= 40°(Vertically Opposite)
40°+x+25°= 180° (Supplementary Angles)
x= 180°- 65°= 115°
y= 115°+25°= 140° (Vertically Opposite)

iv)y= 55° (Vertically Opposite)
x-75°+55°= 180° (Linear Pair)
x-20°= 180°
x= 180°+ 20°= 200°

z= x-75° (Vertically opposite)
z= 200°-75°= 125°


Please mark as the BRAINLIEST answer.